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x^2+2x+2^2=0
We add all the numbers together, and all the variables
x^2+2x+4=0
a = 1; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·1·4
Δ = -12
Delta is less than zero, so there is no solution for the equation
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